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	<title>Comments for </title>
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	<link>http://cookla.wordpress.com</link>
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		<title>Comment on Crossing the bridge. by cookla</title>
		<link>http://cookla.wordpress.com/2009/12/15/crossing-the-bridge/#comment-12</link>
		<dc:creator>cookla</dc:creator>
		<pubDate>Tue, 15 Dec 2009 14:52:04 +0000</pubDate>
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		<description>1 and 2 across (2 minutes)
1 goes back (3 minutes)
5 and 10 go across (13 minutes)
2 goes back (15 minutes)
1 and 2 cross (17 minutes) - and everyone safe and sound</description>
		<content:encoded><![CDATA[<p>1 and 2 across (2 minutes)<br />
1 goes back (3 minutes)<br />
5 and 10 go across (13 minutes)<br />
2 goes back (15 minutes)<br />
1 and 2 cross (17 minutes) &#8211; and everyone safe and sound</p>
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		<title>Comment on mid-semester by cookla</title>
		<link>http://cookla.wordpress.com/2008/10/25/mid-semester/#comment-3</link>
		<dc:creator>cookla</dc:creator>
		<pubDate>Sat, 25 Oct 2008 04:04:50 +0000</pubDate>
		<guid isPermaLink="false">http://cookla.wordpress.com/?p=33#comment-3</guid>
		<description>Note that a bracelet can be rotated or flipped over without changing the basic pattern.
Here is one way to count the possibilities: place all four red beads. There are now four gaps in which
we can place the yellow beads. 1) Place one in each gap. 2) Place all four in one gap. 3 &amp; 4) Place
one in one gap and three in another – either adjacent or opposite. 5 &amp; 6) Place two in each of two
gaps – either opposite or adjacent. 7 &amp; 8) Place two in one gap and one in each of two other
gaps. The two and the empty gap can be either opposite or adjacent.</description>
		<content:encoded><![CDATA[<p>Note that a bracelet can be rotated or flipped over without changing the basic pattern.<br />
Here is one way to count the possibilities: place all four red beads. There are now four gaps in which<br />
we can place the yellow beads. 1) Place one in each gap. 2) Place all four in one gap. 3 &amp; 4) Place<br />
one in one gap and three in another – either adjacent or opposite. 5 &amp; 6) Place two in each of two<br />
gaps – either opposite or adjacent. 7 &amp; 8) Place two in one gap and one in each of two other<br />
gaps. The two and the empty gap can be either opposite or adjacent.</p>
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		<title>Comment on Just another weekend. by cookla</title>
		<link>http://cookla.wordpress.com/2008/09/15/just-another-weekend/#comment-2</link>
		<dc:creator>cookla</dc:creator>
		<pubDate>Tue, 16 Sep 2008 02:24:12 +0000</pubDate>
		<guid isPermaLink="false">http://cookla.wordpress.com/?p=9#comment-2</guid>
		<description>Solution: 102564</description>
		<content:encoded><![CDATA[<p>Solution: 102564</p>
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